Look Outside vs Darkwood

6/10Match score

Higher community rating

Darkwood

+2

rating points

More player ratings

Darkwood

87 ratings

Similarity Breakdown

Same

Game Modes

Same

Perspective

Similar

Genres

Similar

Themes

Different

Features

Shared

Game Modes

Single player

Perspective

Bird view / Isometric

Genres

AdventureIndieRole-playing (RPG)Strategy

Themes

ActionHorrorSurvival

Features

craftingatmospheric

Key Differences

Genres

Look Outside

Turn-based strategy (TBS)

Darkwood

-

Themes

Look Outside

MysteryThriller

Darkwood

-

Features

Look Outside

combat dialogueparty-based combatsurvival horrorelevator musicend of the world

Darkwood

free roamscavengingaction-adventurestory rich

Side-by-Side Comparison

FeatureLook OutsideDarkwood
Release DateMar 21, 2025Aug 17, 2017
Rating80/100 (22 ratings)82/100 (87 ratings)
Genres
AdventureIndieRole-playing (RPG)StrategyTurn-based strategy (TBS)
AdventureIndieRole-playing (RPG)Strategy
Themes
ActionHorrorMysterySurvivalThriller
ActionHorrorSurvival
Features
combat dialoguecraftingparty-based combatsurvival horrorelevator musicend of the worldfungal infectionguitarparty customizationrifletelevisionbombsbugscockroachdialogue choice
craftingfree roamscavengingaction-adventureatmosphericstory rich
Game Modes
Single player
Single player
Player Perspective
Bird view / Isometric
Bird view / Isometric
PlatformsPC (Microsoft Windows)Google Stadia, Linux, Mac, Nintendo Switch, PC (Microsoft Windows), PlayStation 4, PlayStation 5, Xbox One, Xbox Series X|S

Comparison Summary

Look Outside and Darkwood have a 6/10 match score. Both games overlap around Single player, Bird view / Isometric, Adventure, Indie, Role-playing (RPG), Strategy.

Look Outside stands out for Turn-based strategy (TBS), Mystery, Thriller, combat dialogue, while Darkwood stands out for free roam, scavenging, action-adventure.

Darkwood has the higher community rating in the current dataset. Players who enjoy Single player, Bird view / Isometric, Adventure are the most likely to find value in both.

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